A potentiometer wire is 10 m long and has a resistance of 20Ω. It is connected in series with a battery of emf 3V and a resistance of 10Ω. The potential gradient along the wire in Vm−1 is
A
0.01
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B
0.02
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C
0.1
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D
0.2
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Solution
The correct option is D 0.2
r=10Ω,R=20Ωε=3V
i=εR+r=330=0.1A
VR=iR=0.1×20=2V
Potential gradient along the wire is VL=210=0.2Vm−1