Question

A pre-weighed vessel was filled with $O_2$ at STP and weighed. It was then evacuated, filled with $S{O}_2$ at the same temperature and pressure and again weighed. The weight of $O_2$ will be $[O=16,S=32]$.

• A. The same as that of the $S{O}_2$
• B. Twice as that of the $S{O}_2$
• C. Half of that of the $S{O}_2$
• D. One-fourth of that of the $S{O}_2$

Answer 1

The correct option is C Half of that of the $S{O}_2$

Half of that of the $S{O}_2$

Given:-

Wt. of $O_2=32$

Wt. of $S{O}_2=64$

$\therefore \frac{\text{Mol. wt. of}{O}_2}{\text{Mol. wt. of}{O}_2}=\frac{32}{64}=\frac{1}{2}$

$\Rightarrow \text{Mol. wt. of}{O}_2=\frac{1}{2}\text{Mol. wt. of}S{O}_2$

Hence, The weight of $O_2$ will be half of that of the $S{O}_2$.