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Question

# A projectile is thrown in to space so as to have the maximum possible horizontal range equal to 400 m. Taking the point of projection as the origin, the coordinate of the point where the velocity of the projectile is minimum are

A
(400,200)
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B
(200,200)
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C
(400,100)
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D
(200,100)
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Solution

## The correct option is D (200,100)400=u2sin2θg(θ=450 for maximum range)[u2g=400].....(1)Hmax=u2sin2θ2g=u24g=4004=100 mminimum velocity is at top most point = 100 mRange during that instant =Range2 =400/2=200⇒ (200,100) is coordinate of the pointOption D is correct.

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