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Question

# A projectile is thrown so as to have a maximum possible horizontal range of 400 m. Taking the point of projection as the origin, the co-ordinates of the point where the velocity of the projectile is minimum is

A
(400,100)
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B
(200,100)
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C
(400,200)
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D
(200,200)
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Solution

## The correct option is B (200,100)R=u2sin2θg For R to be maximum, sin2θ should be maximum ⇒sin2θ=1⇒2θ=90∘⇒θ=45∘ According to question R=u2g=400 We know that velocity is minimum at the highest point of projectile (i.e. H) By using the relation, Rtanθ=4H 400tan45∘=4H ⇒H=100 ∴ Coordinates of the point where velocity is minimum is (200,100) Hence, the correct answer is option (b). Note: The vertical line passing through highest point divides the Range into two equal parts.

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