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Question

# A projectile is thrown into space so as to have the maximum possible horizontal range equal to 400m. Taking the point of projection as the origin, the coordinates of the point where the velocity of the projectile is minimum are:

A
(400,100)
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B
(200,100)
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C
(400,200)
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D
(200,200)
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Solution

## The correct option is B (200,100) Velocity of the projectile is minimum at the highest point since it has only horizontal component at the highest point. range R=v2sin2θg to maximize θ we have maximize sin2θ hence θ=45o therefore 400=v2g Maximum height will occur at x-coordinate R2=200m Maximum height will be at theta=450 : H=v2sin2θ2g=v24g=4004=100m

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