Question

A $Pt$ complex of ammonia and chlorine produces four ions per molecule in the solution is

• A. $\left[Pt\right(N{H}_3{)}_{5}Cl]C{l}_3$
• B. $\left[Pt\right(N{H}_3{)}_6]C{l}_4$
• C. $\left[Pt\right(N{H}_3{)}_{2}C{l}_4]$
• D. $\left[Pt\right(N{H}_3{)}_{4}C{l}_2]C{l}_2$

Answer 1

The correct option is A $\left[Pt\right(N{H}_3{)}_{5}Cl]C{l}_3$

$\left[Pt\right(N{H}_3{)}_{5}Cl]C{l}_3\to [Pt(N{H}_3{)}_{5}Cl{]}^{+}+3C{l}^{-}$

$\left[Pt\right(N{H}_3{)}_{5}Cl]C{l}_3$ on ionization gives 4 ions in solution i.e $3C{l}^{-}+\left[Pt\right(N{H}_3{)}_{5}Cl{]}^{+}$

Hence option A is correct.