A pump of $200 W$ power is lifting $2 k g$ water per second from an average depth of $10 m$ . The velocity with which water comes out of the pump is :

$(g = 9.8 m s^{- 2})$ .

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A pump is pumping water from the well at a depth of 8 m at the rate of 5 kg per second. The speed of water coming out is 10m/s. The power of the pump is [g=10m/s2]

The correct option is D 650 WPower=work done on gravity + change in KEtimePower=mgh+12mv2t=mt(gh+v22)=5((10×8)+1022)Power=400+250=650 Watt

A pump is pumping water from the well at a depth of 8 m at the rate of 5 kg per second. The speed of water coming out is $10 m / s$ . The power of the pump is $[g = 10 m / s^{2}]$

The correct option is D 650 W
$Power = \frac{work done on gravity + change in KE}{time} Power = \frac{m g h + \frac{1}{2} m v^{2}}{t} = \frac{m}{t} (g h + \frac{v^{2}}{2}) = 5 ((10 \times 8) + \frac{10^{2}}{2}) P o w e r = 400 + 250 = 650 W a t t$