A quantity of electricity required to reduce 12.3 g of nitrobenzene to aniline arising $50 %$ current efficiency is:

1158000C

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579000C

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231600C

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289500C

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Solution

The correct option is A 1158000C
Equivalent mass of nitrobenzene $= \frac{M o l e c u l a r m a s s}{6}$
$= \frac{123}{6} = 20.5$
Number of equivalents of nitrobenzene $= \frac{M a s s}{e q u i v a l e n t m a s s} = \frac{123}{20.5} = 6$
Amount of charge required $= 6 \times 96500 = 579000 c o u l o m b$
Amount of charge required when current efficiency is $50 % = 2 \times 579000$
$= 1158000 C$

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A quantity of electricity required to reduce 12.3 g of nitrobenzene to aniline arising 50% current efficiency is:

The correct option is A 1158000CEquivalent mass of nitrobenzene =Molecular mass6 =1236=20.5 Number of equivalents of nitrobenzene =Massequivalent mass=12320.5=6 Amount of charge required =6×96500=579000 coulomb Amount of charge required when current efficiency is 50%=2×579000 =1158000 C

A quantity of electricity required to reduce 12.3 g of nitrobenzene to aniline arising $50 %$ current efficiency is: