A radar has a power of 1 kW and is operating at a frequency of 10 GHz. It is located on a mountain top, of height 500 m. The maximum distance upto which it can detect object located on the surface of the earth is:
(Radius of earth $= 6.4 \times 10^{6} m$ )

80 km

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16 km

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40 km

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64 km

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Solution

The correct option is A 80 km
Maximum distance on earth where object can be detected is d, then
$(h + R)^{2} = d^{2} + R^{2}$
$d^{2} = h^{2} + 2 R h$
Since $h << R$ , $d^{2} = 2 h R$
$d = 2 (500) (6.4 \times 106) = 80 k m$

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A radar has a power of 1 kW and is operating at a frequency of 10 GHz. It is located on a mountain top, of height 500 m. The maximum distance upto which it can detect object located on the surface of the earth is:(Radius of earth =6.4×106m)

The correct option is A 80 kmMaximum distance on earth where object can be detected is d, then(h+R)2=d2+R2d2=h2+2Rh Since h<<R, d2=2hR d=2(500)(6.4×106)=80km

A radar has a power of 1 kW and is operating at a frequency of 10 GHz. It is located on a mountain top, of height 500 m. The maximum distance upto which it can detect object located on the surface of the earth is:
(Radius of earth $= 6.4 \times 10^{6} m$ )

The correct option is A 80 km
Maximum distance on earth where object can be detected is d, then
$(h + R)^{2} = d^{2} + R^{2}$
$d^{2} = h^{2} + 2 R h$
Since $h << R$ , $d^{2} = 2 h R$
$d = 2 (500) (6.4 \times 106) = 80 k m$