A radar has a power of 1 kW and is operating at a frequency of GHz. It is located on mountain top of height 500 m The maximum distance up to which it can detect object located on the surface of the earth
(Radius of earth $6.4 \times 10^{6} m$ )is:

40 km

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80 km

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16 km

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Solution

The correct option is C 80 km
Maximum distance on earth where object can be detected is $d$ , then,
$(h + R)^{2} = d^{2} + R^{2} d^{2} = h^{2} + 2 R h d = \sqrt{2 (500) (6.4 \times 10^{6})} = 80 k m$

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A radar has a power of 1 kW and is operating at a frequency of GHz. It is located on mountain top of height 500 m The maximum distance up to which it can detect object located on the surface of the earth (Radius of earth 6.4×106m)is:

The correct option is C 80 kmMaximum distance on earth where object can be detected is d , then,(h+R)2=d2+R2d2=h2+2Rhd=√2(500)(6.4×106)=80km

A radar has a power of 1 kW and is operating at a frequency of GHz. It is located on mountain top of height 500 m The maximum distance up to which it can detect object located on the surface of the earth
(Radius of earth $6.4 \times 10^{6} m$ )is:

The correct option is C 80 km
Maximum distance on earth where object can be detected is $d$ , then,
$(h + R)^{2} = d^{2} + R^{2} d^{2} = h^{2} + 2 R h d = \sqrt{2 (500) (6.4 \times 10^{6})} = 80 k m$