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Question
A radioactive element AZX loses two successive β−particles and an α−particles such that resulting element is PQY. Find the values of P and Q in terms of A and Z.
A radioactive element AZX loses two successive β−particles and an α−particles such that resulting element is PQY. Find the values of P and Q in terms of A and Z.
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Solution
The correct option is D A−4ZY
The symbolic representation of the reaction is as follows:
AZXβ−particle−−−−−−→Mβ−particle−−−−−−→Nα−particle−−−−−−→PQY
From the above, the symbol of
M=AZ+1M and N=AZ+2N
Since, N element loses one alpha - particle, therefore, the new element has:
mass number = A - 4
Atomic number = Z + 2 - 2 = Z
Hence, P = A - 4 and Q = Z
A−4ZY
The symbolic representation of the reaction is as follows:
AZXβ−particle−−−−−−→Mβ−particle−−−−−−→Nα−particle−−−−−−→PQY
From the above, the symbol of
M=AZ+1M and N=AZ+2N
Since, N element loses one alpha - particle, therefore, the new element has:
mass number = A - 4
Atomic number = Z + 2 - 2 = Z
Hence, P = A - 4 and Q = Z
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