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Question

A ray of light is incident at 60, on a glass-air interface. Then the light ray will be ___.

Use : [μglass = 2 , μair = 1]



A

refracts at 30°

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B

reflects back into glass

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C

refracts at 90°

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D

none of these

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Solution

The correct option is B

reflects back into glass


ic = sin1 1μglass

ic = sin1 12 μw = 2
We get ic=45

As angle of incidence > ic

Hence Total Internal Reflection occurs.


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