A ray of light travelling from glass to air is incident at 60∘ on the interface. The light ray will:
Use : [μglass = √2, μair = 1]
reflect back into glass
Rays of light is travelling from denser to rarer medium, so there is a chance of total internal reflection if angle of incidence is greater than the critical angle.
Let the critical angle be ic
ic = sin−1 1μglass
ic = sin−1 1√2 (∵μg = √2)
We get ic=45∘
As, angle of incidence > ic
Hence, total internal reflection occurs.