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Question

A reactor is developing energy at the rate of 32 MW. Calculate the required number of fissions per second of 92U235. Assume that energy per fission is 200 MeV

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Solution

Rate at which the energy is developed at the reactor =32 MW=32×106J/s
Energy per fission =200 MeV
Required number of fissions per second =?
Since the two energies are in different units, we must convert them into the same unit.
energy released per fission =200 MeV
=200×106eV
=200×106×1.6×1019J(1eV=1.6×1019J)
=320×1013Joules.
Let N be the number of fissions per second producing 32 MW.
Energy per fission ×N= Total energy released per second
320×1013×N=32×106J/s
N=32×106320×1013=1018fissions
The no. of fissions per second to produce the required power =1018 fissions per second.

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