Question

A right angled triangle has a hypotenuse, base and the perpendicular side. Let angle $A$ be the angle between the base and the hypotenuse. Draw and find $\tan A$.

Answer 1

From the triangle above, $\tan A=\frac{\text{opposite}}{\text{adjacent}}=\frac{BC}{AB}$.

In this triangle, opposite is the side opposite to angle $A$ which is $BC$ and adjacent is the side which lies adjacent to the angle $A$, i.e. $AB$.