A road is being designed for a speed of 110 km/hr on a horizontal curve with a super elevation of 8%. If the coefficient of side friction is 0.10, the minimum radius of the curve (in m) required for safe vehicular movement is

528.5

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115.0

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264.3

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152.3

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Solution

The correct option is A 528.5
$e + f = \frac{(0.278 V)^{2}}{g R}$

$\Rightarrow e + f = \frac{V^{2}}{127 R}$

$\Rightarrow R = \frac{V^{2}}{127 (e + f)}$

$= \frac{(110)^{2}}{127 (0.08 + 0.1)}$

$= 528.5 m$

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A road is being designed for a speed of 110 km/hr on a horizontal curve with a super elevation of 8%. If the coefficient of side friction is 0.10, the minimum radius of the curve (in m) required for safe vehicular movement is

The correct option is A 528.5e+f=(0.278V)2gR ⇒e+f=V2127R ⇒R=V2127(e+f) =(110)2127(0.08+0.1) =528.5 m

The correct option is A 528.5
$e + f = \frac{(0.278 V)^{2}}{g R}$

$\Rightarrow e + f = \frac{V^{2}}{127 R}$

$\Rightarrow R = \frac{V^{2}}{127 (e + f)}$

$= \frac{(110)^{2}}{127 (0.08 + 0.1)}$

$= 528.5 m$