A room is $6$ meters $24$ centimeters in length and $4$ meters $32$ centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the room?

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Solution

Length $= 6 m 24 c m = 624 c m$

Width $= 4 m 32 c m = 432 c m$

HCF of $624$ and $432 = 48$
Number of square tiles required = $\frac{624 \times 432}{48 \times 48}$ = $13 \times 9 = 117$

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A room is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the room?

Length =6 m 24 cm=624 cmWidth =4 m 32 cm=432 cmHCF of 624 and 432=48Number of square tiles required = 624×43248×48 = 13×9=117

A room is $6$ meters $24$ centimeters in length and $4$ meters $32$ centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the room?

Length $= 6 m 24 c m = 624 c m$

Width $= 4 m 32 c m = 432 c m$

HCF of $624$ and $432 = 48$
Number of square tiles required = $\frac{624 \times 432}{48 \times 48}$ = $13 \times 9 = 117$