Question

A sample of 0.469 g of chloroplatinate of a monoacidic base on decomposition gave 0.195 g of platinum. The molecular formula of the base can be

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

1 mole of $B_2{H}_{2}PtC{l}_6\stackrel{\Delta }{\to }1$ mole of Pt
1 mole of Pt weighs 195 g.
$\therefore$ 469 g of the chloroplatinate yields 1 mole of Pt.
Molar Mass of the chloroplatinate = 469.
Molar Mass of the Base = 469 – 410 = 59.
Molar Mass of 59 corresponds to the formula (c) .