A short bar magnet is placed with its south pole facing geographic south and the distance between the null points is found to be 16 cm. When the magnet is turned pole to pole at the same place then the distance between the null points will be:

same along the axial line

No worries! We‘ve got your back. Try BYJU‘S free classes today!

same along the equatorial line

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 \times 2^{\frac{1}{3}}

times on the axial line

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{16}{2^{\frac{1}{3}}}

times on the equatorial line

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{16}{2^{\frac{1}{3}}}$ times on the equatorial line
$B_{1}$ for axial and $B_{2}$ for equatorial
$(d_{1} = 16)$
$B_{1} = \frac{2 μ_{o} m}{4 π d_{1}^{3}}$
$B_{2} = \frac{μ_{o} m}{4 π d_{2}^{3}}$
$B_{1} = B_{2}$
$d_{2} = \frac{16}{2^{1 / 3}}$

Suggest Corrections

Similar questions

Q. A short bar magnet of moment

4 {Am}^{2}

is placed in the magnetic meridian with its south-pole pointing geographic north. The distance between two null points is found to be

20 cm

(i i i)

If the same magnet is placed with its north pole pointing geographic north, then the distance between the null points

(use 4^{\frac{1}{3}} = 1.59)

Q. The null points are on the axial line of a bar magnet, when it is placed such that its south pole points

If we place a bar magnet in the magnetic meridian with its north pole towards geographical North, the neutral point will be

1.on the axial of the magnet

2.on the equatorial line line of magnet

3.at 45 with the axial line

4. At 45 with equatorial line

Q. A short bar magnet of moment

4 {Am}^{2}

is placed in the magnetic merdian with its south-pole pointing geographic north. The distance between two null points is found to be

20 cm

(i i)

If the magnet is turned through

90^{\circ}

, the resultant field at the location of the null point will be.

A short bar magnet is placed with its south pole pointing geographic North at a place where $B_{H} = 0.4$ gauss. The length of the magnet is $10 c m$ and pole strength is $16 A - m$ . The distance of each null point from the centre will be

Join BYJU'S Learning Program

A short bar magnet is placed with its south pole facing geographic south and the distance between the null points is found to be 16 cm. When the magnet is turned pole to pole at the same place then the distance between the null points will be:

The correct option is D 16213 times on the equatorial lineB1 for axial and B2 for equatorial (d1=16)B1=2μom4πd31B2=μom4πd32B1=B2d2=1621/3

The correct option is D $\frac{16}{2^{\frac{1}{3}}}$ times on the equatorial line
$B_{1}$ for axial and $B_{2}$ for equatorial
$(d_{1} = 16)$
$B_{1} = \frac{2 μ_{o} m}{4 π d_{1}^{3}}$
$B_{2} = \frac{μ_{o} m}{4 π d_{2}^{3}}$
$B_{1} = B_{2}$
$d_{2} = \frac{16}{2^{1 / 3}}$