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Question

A short electric dipole has dipole moment of 2.4×1010 C-m. The electric potential due to the dipole at a point at a distance of 0.4 m from the centre of the dipole situated on a line making an angle 60 with the dipole axis is -

A
3.25 V
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B
4.55 V
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C
6.75 V
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D
12.50 V
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Solution

The correct option is C 6.75 V
The electric potential at any general point due to an electric dipole is given by,

V=pcosθ4πϵ0r2

Here, p=2.4×1010 C-m,r=0.4 m

So,

V=2.4×1010×cos60×9×109(0.4)2=6.75 V

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