You visited us 2 times! Enjoying our articles? Unlock Full Access!

Heating Effect of Electric Current

A simple circ...

Question

A simple circuit consisting of three resistors is shown above. $R_{1}$ has the same resistance of $R_{2}$ and $R_{2}$ has twice the resistance of $R_{3}$ . If the switch remains closed, determine the ratio of heat dissipated of $R_{1}$ to $R_{2}$ .

1:9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9:1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is E 9:1
$R_{1} = R_{2} = 2 R_{3} = 2 R (l e t)$
Let the current in $R_{1}$ be $i$ .
Then current in $R_{2} = \frac{i R_{3}}{R_{2} + R_{3}} = \frac{i}{3}$
Hence ratio of heat dissipated in the resistors= $\frac{i^{2} R_{1}}{(\frac{i}{3})^{2} R_{2}}$
$= 9 : 1$

Suggest Corrections

Similar questions

R_{1}

R_{2}

R_{1}

R_{2}

R_{1}

R_{2}

R_{1}

R_{2}

R_{1}

R_{1}, R_{2}

R_{3}

R_{3}

1 Ω

R_{3}

R_{1}

R_{2}

R_{1}

R_{2}

(a \times 2 a \times 4 a)

R_{1}

R_{2}

R_{3}

Join BYJU'S Learning Program