A skydiver weighing 60 kg moves through a distance of 40 m upwards in 2 seconds. The power spent by the skydiver due to its weight (in Watt) is ___ . $T a k e g = 9.8 m / s^{2}$

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Solution

Power spent by the skydiver = $\frac{w o r k d o n e}{t i m e}$

Work done in 2 seconds = force $\times$ displacement
Since the force exerted is same as the weight of the skydiver, $F = m g = 60 \times 9.8 = 588 N$
Work done = force x displacement $= (588 \times 40) J$
So, power spent in 2 seconds $= (\frac{588 \times 40}{2}) W = 11760 W = 11.76 K W$

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A skydiver weighing 60 kg moves through a distance of 40 m upwards in 2 seconds. The power spent by the skydiver due to its weight (in Watt) is ___ . Take g =9.8 m/s2

Power spent by the skydiver = work donetime Work done in 2 seconds = force × displacement Since the force exerted is same as the weight of the skydiver, F=mg =60×9.8=588 N Work done = force x displacement=(588×40) J So, power spent in 2 seconds =(588×402) W=11760 W=11.76 KW

A skydiver weighing 60 kg moves through a distance of 40 m upwards in 2 seconds. The power spent by the skydiver due to its weight (in Watt) is ___ . $T a k e g = 9.8 m / s^{2}$