A skydiver who weighs 60 kg is moving at terminal speed. He covers 40 m in 2 seconds. The rate of doing work by the sky diver is ___ .

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Solution

Power spent by the skydiver = $\frac{w o r k d o n e}{t i m e}$

Work done in 2 seconds = Force x Displacement
$= (60 \times 10 \times 40) J$
So, power spent in 2 seconds $= (60 \times 10 \times \frac{40}{2}) W$

$= 12000 W$

$= 12 K W$

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A skydiver who weighs 60 kg is moving at terminal speed. He covers 40 m in 2 seconds. The rate of doing work by the sky diver is ___ .

Power spent by the skydiver = work donetime Work done in 2 seconds = Force x Displacement =(60×10×40) J So, power spent in 2 seconds =(60×10×402) W =12000 W =12 KW

Power spent by the skydiver = $\frac{w o r k d o n e}{t i m e}$

Work done in 2 seconds = Force x Displacement
$= (60 \times 10 \times 40) J$
So, power spent in 2 seconds $= (60 \times 10 \times \frac{40}{2}) W$

$= 12000 W$

$= 12 K W$