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Moment of Inertia of an Annular Disc

A solid cylin...

Question

A solid cylinder of mass $20 K g$ has length $1 m$ and radius $0.2 m$ . Then its moment of inertia $(i n k g - m^{2})$ about its geometrical axis is-

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Solution

$∵ I = \frac{M R^{2}}{2} f o r s o l i d c y l i n d e r I = \frac{20 \times (0.2) \times (0.2)}{2} I = 0.4 k g m^{2}$

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