Question

A solution $\left(5mL\right)$ of an acid X is completely neutralized by y mL of $1$M NaOH. The same volume (y ml) of $1$M NaOH is required to neutralize $10$mL of $0.6$M of $H_{2}S{O}_4$ completely. The normality(N) of the acid X is?

• A. $1.2$
• B. $2.4$
• C. $4.8$
• D. $0.6$

Answer 1

Answer: (B)

$2.4$

$N_1\times V_1=N_2\times V_2$

$5\times X=y\times 1$

For second case

$y\times 1=10\times 2\times 0.6$ ($H_{2}S{O}_4$ dissociates to give 2 $H^{+}$ ions)

So $y=12ml$

Put in above equation vale of $y$

we get $X=2.4M$