A solution of colourless salt 'S' on boiling with excess $N a O H$ produces a non-flammable gas. The evolution of the gas ceases after sometime. Upon addition of $Z n$ dust to the same solution, the gas is evolved again. The colourless salt(s) 'S' can be:

N H_{4} N O_{3}

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N H_{4} N O_{2}

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N H_{4} C l

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(N H_{4})_{2} S O_{4}

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Solution

The correct options are
A $N H_{4} N O_{3}$
B $N H_{4} N O_{2}$
$N H_{4} N O_{3} + N a O H \to N H_{3} + N a N O_{3} + H_{2} O$
$7 N a O H + N a N O_{3} + 4 Z n \to 4 N a_{2} Z n O_{2} + N H_{3} + 2 H_{2} O$

$N H_{4} N O_{2} + N a O H \to N a N O_{2} + N H_{3} + H_{2} O$
$3 Z n + 5 N a O H + N a N O_{2} \to 3 N a_{2} Z n O_{2} + N H_{3} + H_{2} O$

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Similar questions

H_{2} S O_{4}

(A) + N a O H (e x c e s s) Δ ⟶ g a s (B)

H C l + a l k a l i n e s o l u t i o n (C)

(C) + Z n ⟶ g a s (B)

(A) Δ ⟶ g a s (D) + l i q u i d (E)

D, E

(A, B, C, D)

(E)

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