A solution of H3PO4 is 98% by mass. Calculate the molarity and normality if the density of the solution is 1.8 g/mL.
A
18 M, 18 N
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B
18 M, 54 N
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C
6 M, 18 N
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D
54 M, 18 N
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Solution
The correct option is B 18 M, 54 N Let the mass of the solution be 100 g.
98% by mass H3PO4 means 98 g of H3PO4 is present in 100 g of the solution.
Number of moles = given massmolar mass=9898=1mol
Density = massvolume ⇒ volume of the solution = 1001.8 mL
Molarity=moles of solutetotal volume of solution (in mL)×1000=11001.8×1000 Molarity=18M
Normality = Molarity × n-factor
(n-factor for H3PO4 is 3)
Normality = 54 N