wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A solution of sucrose (molar mass = 342 g/mol) is prepared by dissolving 68.4 g of it per litre of the solution. What is its osmotic pressure (R = 0.082 lit. atm.k-1mol-1) at 273 K?

A

6.02 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

4.92 atm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

4.04 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

5.32 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

Weight given (sucrose) = 68.4 gram

Gas constant (R) = 0.082 lit. atm.K1 mol1

Temperature = 273 K

Molecular mass = 342 gm/mol

V = 1

Hence using the formula of osmotic pressure we get

π=w×R×Tmolarmass×Volume

π=68.4×0.082×273342

π=4.48atm





flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Osmotic Pressure
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon