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Question

A spring is compressed between two blocks of masses m1 and m2 placed on a horizontal frictionless surface. When the blocks are released, the blocks travel distance x1 and x2 respectively before coming to rest. The ratio x1/x2 is:

A
m1/m2
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B
m2/m1
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C
m1m2
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D
m2m1
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Solution

The correct option is D m2/m1
Initial momentum of the system is zero i.e. Pi=0
Let the velocity acquire by masses m1 and m2 just after they are released be v1 and v2.
Final momentum of the system Pf=m1v1m2v2
Using conservation of momentum : Pi=Pf
0=m1v1m2v2
m1v1=m2v2 (v=dxdt)
m1x1=m2x2
x1x2=m2m1

686470_305792_ans_a2c414cd6b824aa2a46c814ef642f791.png

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