Question

A square board side $10$ centimeters standing vertically is tilted to the left so that the bottom right corner is raised $6$ centimeters from the ground. By what distance is the top left corner lowered from its original position ?

• A. $1$ cm
• B. $2$ cm
• C. $3$ cm
• D. $0.5$ cm

Answer 1

Answer: (B)

$2$ cm

A square board side $10$ centimeters standing vertically.
It tilted to the left so that the bottom right corner is raised 6 centimeters from the ground.
So its one side corner length was $x$ cm from ground
Then $x^2={10}^2-6^2=100-36=64$ cm
$x=8cm$

Then distance is the top left corner lowered from its original position $=10-8=2$ cm

Hence, option B.