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Question

# A square frame of edge 5 cm is placed with its positive normal making an angle of 60∘ with a uniform electric field of 200 N/C. Find the electric flux through the surface bounded by the frame.

A
0.15 N-m2/C
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B
0.25 N-m2/C
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C
0.35 N-m2/C
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D
0.45 N-m2/C
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Solution

## The correct option is B 0.25 N-m2/CGiven: Edge of square frame, a=5 cm So, area of square frame, A=a2=25 cm2=25×10−4 m2 Angle made by positive normal of area with electric field, θ=60∘ Magnitude of electric field, E=200 N/C We know that electric flux ϕ is given by ϕ=→E.→A=EAcosθ ⇒ϕ=200×25×10−4×cos60∘ ⇒ϕ=0.25 N-m2/C

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