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Question

A square PQRS and an equilateral triangle XYZ are rearranged to form a figure as shown.

What is the perimeter of the ABDF ? (Take 2 = 1.4 and 3 = 1.7)


A

25 cm

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B

31 cm

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C

24.4 cm

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D

32.4 cm

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Solution

The correct option is C

24.4 cm


To find the perimeter of ABDF, we need to know the following sides :

AB, BD, DF and AF

AB = XO (height of the equilateral XYZ)

= XY2YO2

= 8242

= 6416

= 48 = 43 cm

BD = 8 cm (side of equilateral XYZ)

DF = 4 cm (side of square PQRS)

AF = Diagonal of square

= PQ2+QR2

= 42+42

= 32 = 42 cm

Perimeter of ABDF = AB + BD + DF + AF

= 43 + 8 + 4 + 42

= 6.8 + 12 + 5.6

= 24.4 cm


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