A stone dropped from the top of the tower reaches ground in $4 s e c$ . Height of the tower is $(g = 10 m / s^{2})$

20 m

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40 m

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60 m

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80 m

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Solution

The correct option is D $80 m$
Initial speed of the stone $u = 0 m / s$

Time taken by the stone to reach the ground $t = 4 s$

Height of the tower $H = u t + \frac{1}{2} a t^{2}$

$∴$ $H = 0 + \frac{1}{2} \times 10 \times 4^{2}$

$⟹$ $H = 80 m$

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A stone dropped from the top of the tower reaches ground in 4 sec. Height of the tower is (g=10m/s2)

The correct option is D 80mInitial speed of the stone u=0m/sTime taken by the stone to reach the ground t=4sHeight of the tower H=ut+12at2∴ H=0+12×10×42⟹ H=80m

A stone dropped from the top of the tower reaches ground in $4 s e c$ . Height of the tower is $(g = 10 m / s^{2})$

The correct option is D $80 m$
Initial speed of the stone $u = 0 m / s$

Time taken by the stone to reach the ground $t = 4 s$

Height of the tower $H = u t + \frac{1}{2} a t^{2}$

$∴$ $H = 0 + \frac{1}{2} \times 10 \times 4^{2}$

$⟹$ $H = 80 m$