Question

A stone falls freely under gravity, covers distance $h_1,h_2$ and $h_3$ in the first 5 sec, the next 5 sec and the further next 5 sec respectively. The relation between $h_1,h_2$ and $h_3$ is:

• A. $h_1=2h_2=3h_3$
• B. $h_1=\frac{h_2}{3}=\frac{h_3}{5}$
• C. $h_3=3h_1$ and $h_1=3h_2$
• D. $h_1=h_2=h_3$

Answer 1

The correct option is B

$h_1=\frac{h_2}{3}=\frac{h_3}{5}$

$h_1=\frac{1}{2}g\times t_1^2{t}_1=5sec{h}_1=125m{h}_2=\frac{g}{2}\left[\right(10{)}^2]-125=375m{h}_3=\frac{g}{2}[(15{)}^2-(10{)}^2]=625h_1:h_2:h_3=125:375:625125:375:625h_1=\frac{h_2}{3}=\frac{h_3}{5}$