A stone is projected from the top of a tower with velocity 20m/s making an angle of elevation of 30o with the horizontal. If the total time of flight is 5s and g=10m/s2, then
A
the height of the tower is 75m.
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B
the maximum height of the stone from the ground is 80m.
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C
both A and B are true.
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D
the height of the tower is 120m.
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Solution
The correct option is D both A and B are true. Sy=ut−12gt2
h=Sy=20sin30o×5−12×10×(5)2 h=50−125=−75m (minus sign just indicates that the displacement is in downward direction)
hmax=u2sin2θ2g=(20)2sin23002×10=5m
Hence, maximum height attained by projectile =h+hmax=75+5=80m