Question

A stone is thrown at an angle $\theta$ to the horizontal reaches a maximum height H. Then the time of flight of stone will be

• A. $\sqrt{\frac{2H}{g}}$
• B. $2\sqrt{\frac{2H}{g}}$
• C. $\frac{2\sqrt{2Hsin\theta }}{g}$
• D. $\frac{\sqrt{2Hsin\theta }}{g}$

Answer 1

The correct option is B $2\sqrt{\frac{2H}{g}}$

$H=\frac{u^{2}si{n}^2\theta }{2g}andT=\frac{2usin\theta }{g}\Rightarrow T^2=\frac{4u^{2}si{n}^2\theta }{g^2}$
$\therefore \frac{T^2}{H}=\frac{8}{g}\Rightarrow T=\sqrt{\frac{8H}{g}}=2\sqrt{\frac{2H}{g}}$