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Question

A stone is thrown vertically upwards with a speed of 20 m/s. How high will it go before it begins to fall ? (g=9.8m/s2)



    Solution

    The correct option is

    Given :

    Initial velocity u = +20 m/s

    Find velocity v = 0 m/sec

    Gravity acceleration g = 9.8 m/s2

    Distance s = ?

    From 3rd equation of motion

    v2u2 = 2as

    02(+20)2= 2 × 9.8 × s

    - 400 = 2 × 9.8 × s

    s = −400/2×9.8 = – 20.4 m

    Negative sign shows direction of displacement and gravity acceleration are opposite direction.

    the distance = 20.4 m

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