A stone is thrown vertically upwards with an initial velocity of $14 m s^{- 1}$ . Find the time taken by the stone to strike the ground. (Take $g = 9.8 m s^{- 2}$ )

2.86 s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.46 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3.86 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.86 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2.86 s$
A stone is thrown vertically upwards with an initial velocity of 14m/s.
since the velocity at top is zero.
$t = \frac{v - u}{a} = \frac{14}{9.8} = 1.43 s e c$

The time taken by the stone to strike the ground will be $2 t = 2 \times 1.43$
$t^{'} = 2.86 s e c$

Suggest Corrections

Similar questions

40 m s^{- 1}

10 m s^{- 2}

49 m s^{- 1}

g = 9.8 m s^{- 2}

30 m/s

g = 10 {m/s}^{2}

40 m s^{- 1}

g = 10 m s^{- 2}

\frac{g}{8} {ms}^{- 2}

8 s

(g = 9.8 {ms}^{- 2})

Join BYJU'S Learning Program