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Motion Under Gravity

A stone throw...

Question

A stone thrown upward with a speed 'u' from the top of the tower reaches the ground with a velocity '3u'. The height of the tower is :-

A

\frac{3 u^{2}}{g}

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B

\frac{4 u^{2}}{g}

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C

\frac{6 u^{2}}{g}

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D

\frac{9 u^{2}}{g}

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Solution

The correct option is B $\frac{4 u^{2}}{g}$
$v^{2} = u^{2} + 2 a s (3 u)^{2} = u^{2} + 2 g s s = \frac{{9 u}^{2} - u^{2}}{2 g} = \frac{4 u^{2}}{g}$

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