A system consists of Block A and B of masses 5kg each and connected to a pulley as shown in figure. Find the minimum value of force F at which they will start moving? (Assume g=10m/s2).
A
60N
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B
30N
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C
120N
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D
90N
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Solution
The correct option is A60N Let us find the forces acting on each block, so the FBDs of the blocks are as shown
From the FBDs we have N1=5g=50N
The static friction between block A and B is f2s=μ2s(N1)=0.6(50)=30N
Now, as per the question, the blocks just start moving, means, the friction will be limiting friction.
So, for block B: T=f2s For block A: T+f2s=F ⇒F=2f2s=2×30=60N
Hence, if the force F is above 60N, they will move.