A system is changed from state A to state B by one path and from B to A by another path. If $△ U_{1}$ and $△ U_{2}$ are the corresponding changes in internal energy, then:-

△ U_{1} + U_{2} = + v e

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△ U_{1} + U_{2} = - v e

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△ U_{1} + U_{2} = 0

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None of the above

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Solution

The correct option is C $△ U_{1} + U_{2} = 0$
The system is going from A to B $(△ U_{1})$ and then B to A $(△ U_{2})$
As the initial and final states are same, and we know internal energy is a state function.
So,
$Δ U_{t o t a l} = 0$
This means,
$△ U_{1} + U_{2} = 0$

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The internal energy change when a system goes from state $A$ to $B$ is $40 k J m o l e^{- 1}$ . If the system goes from $A$ to $B$ by a reversible path and returns to state $A$ by an irreversible path, what would be the net change in internal energy?

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A system is changed from state A to state B by one path and from B to A by another path. If △U1 and △U2 are the corresponding changes in internal energy, then:-

The correct option is C △U1+U2=0The system is going from A to B (△U1) and then B to A (△U2) As the initial and final states are same, and we know internal energy is a state function. So, ΔUtotal=0 This means, △U1+U2=0

A system is changed from state A to state B by one path and from B to A by another path. If $△ U_{1}$ and $△ U_{2}$ are the corresponding changes in internal energy, then:-

The correct option is C $△ U_{1} + U_{2} = 0$
The system is going from A to B $(△ U_{1})$ and then B to A $(△ U_{2})$
As the initial and final states are same, and we know internal energy is a state function.
So,
$Δ U_{t o t a l} = 0$
This means,
$△ U_{1} + U_{2} = 0$