A thermodynamic system is taken through the cycle $A B C D$ as shown in figure. If $O_{2}$ gas is taken through $A B C D$ , then net heat absorbed is $H_{1}$ . Now if Helium gas is taken through $A B C D$ , net heat absorbed is $H_{2}$ . Find $\frac{H_{1}}{H_{2}}$ .

5 : 3

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7 : 5

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32 : 4

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1 : 1

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Solution

The correct option is D $1 : 1$
Heat absorbed = total work done
Heat absorbed = area bounded by $P - V$ graph
$= 2 P_{0} V_{0}$ (same for all gases)
$\frac{H_{1}}{H_{2}} = 1$

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