Question

A three-span continuous beam has an internal hinge at B. Section B is at the mid-span of AC. Section E is at the mid-span of CG. The 20 kN load is applied at section B whereas 10 kN loads are applied at sections D and F as shown in the figure. Span GH is subjected to uniformly distributed load of magnitude 5 kN/m. For the loading shown, shear force immediate to the right of section E is 9.84 kN upwards and the hogging moment at section E is 10.31 kN-m.



AB = BC = 2 m ; CD = DE = EF = FG = 1 m; GH = 4 m

The vertical reaction at support H is

• A. 15 kN upward
• B. 9.84 kN upward
• C. 15 kN downward
• D. 9.84 kN downward

Answer 1

The correct option is B 9.84 kN upward


$M_E=10.31kNm$

Shear force right of section $E_0$

$V_E^{+}=9.84KN$ upward

Hogging moment at E,

$M_E=10.31kNm$

At support G

Hogging moment from left side = Hogging moment from right side

$10.31+10\times 1-9.84\times 2$

$=\frac{5.(4{)}^2}{2}$ $-R_H\times 4$

$\Rightarrow$ $R_H=9.84kN$ (upward)