Question

A tile is a square of side $25\text{cm}$ . How many such tiles would be required to cover the floor of a square bathroom of side $3\text{m}$ ?

Answer 1

Finding the number of tiles

Side of the square tile $=25\text{cm}$

Area of the square tile $=\text{side×side}$

$=25\times 25=625{\text{cm}}^2$

Now, we find the area of square bathroom

Side of the bathroom $=3\text{m}$

Area of the bathroom $=3\times 3=9{\text{m}}^2$

We know that $1\text{m=100 cm}$

Area of the bathroom in ${\text{cm}}^2{\text{= 9×100×100=90000 cm}}^2$

So the number of tiles $=$ $\frac{\text{Area of bathroom}}{\mathrm{Area}\mathrm{of}1\mathrm{square}\mathrm{tile}}$

$$\begin{gathered} =\frac{90000}{625} \\ =144 \end{gathered}$$

Hence, number of tiles required are $144$