You visited us 1 times! Enjoying our articles? Unlock Full Access!

Torque

A torque of 2...

Question

A torque of 20 Nm is applied on a wheel having angular momentum of $2 k g m^{2} / s$ , calculate the angular momentum of the wheel after 4 seconds.

80 k g m^{2} / s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

55 v

No worries! We‘ve got your back. Try BYJU‘S free classes today!

45 k g m^{2} / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

22 k g m^{2} / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $80 k g m^{2} / s$
L1= angular momentum $2 k g m^{2} / s$
L = final angular momentum = ?
= torque applied on wheel = 20 Nm
according to impulse -change in angular momentum equation
Torque x time interval = change in angular momentum
Using the equation
t = (L - L)
inserting the values in the above equation
20(4)=(L2-L1)
80=L2-2
L2= $80 k g m^{2} / s$

Suggest Corrections

Similar questions

50 N m

10 k g m^{2} s - 1

2 s

(i n {k g m}^{2} s^{- 1})

1000 k g - m^{2}

10 r a d / s

100

100 r a d / s

A_{0}

4 A_{0}

4 s

400

10

20

A

4 A

4

Join BYJU'S Learning Program