Question

A torque of $50Nm$ is applied on a wheel having initial angular momentum of $10kg{m}^{2}s-1$. The angular momentum of wheel after $2s$ $\left(in{kgm}^2{s}^{-1}\right)$ is

• A. 100
• B. 110
• C. 120
• D. 55

Answer 1

The correct option is B 110

$\begin{array}{c}\pi =\frac{dL}{dt}\Rightarrow \text{Torque}p=\frac{L_2-L}{t}\\ L_2={\tau }_t+L_1=50\times 2+10\\ =110\\ \text{Where}L\text{is angular momentum}\\ \text{Hence option}B\text{is correct}\end{array}$