A train moving with a velocity of $20 m s^{- 1}$ is brought to rest by applying the brakes in 5 s. Calculate the retardation.

4 m s^{- 2}

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2 m s^{- 2}

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1 m s^{- 2}

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8 m s^{- 2}

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Solution

The correct option is A $4 m s^{- 2}$
$u = 20 m / s, v = 0, t = 5 s$
$v = u + a t$
$0 = 20 + a \times 5$
$a = - 4 m / s^{2}$
Therefore, $Retardation = 4 m / s^{2}$

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