A train takes 2 h to reach to station B from station A and then 3 h to return from station B to station A. The distance between the two stations is 200 km. Find the average speed.

40 k m h^{- 1}

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80 k m h^{- 1}

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\frac{1000}{6} k m h^{- 1}

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None of the above.

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Solution

The correct option is B $80 k m h^{- 1}$
Total distance travelled = $200 k m + 200 k m = 400 k m$
Total time of journey = $2 h + 3 h = 5 h$
Therefore, Average Speed $= \frac{400 k m}{5 h} = 80 k m / h$

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A train takes 2 h to reach to station B from station A and then 3 h to return from station B to station A. The distance between the two stations is 200 km. Find the average speed.

The correct option is B 80 kmh−1Total distance travelled = 200km+200km=400kmTotal time of journey = 2h+3h=5hTherefore, Average Speed =400km5h=80km/h

The correct option is B $80 k m h^{- 1}$
Total distance travelled = $200 k m + 200 k m = 400 k m$
Total time of journey = $2 h + 3 h = 5 h$
Therefore, Average Speed $= \frac{400 k m}{5 h} = 80 k m / h$