Question

A transmitter installed at Byju's headoffice operates at a frequency of 99 MHz and power of 20 kW, then the number of photons emitted per second is

• A. $3\times {10}^{29}$
• B. $3\times {10}^{20}$
• C. $3\times {10}^{34}$
• D. $3\times {10}^{19}$

Answer 1

The correct option is A $3\times {10}^{29}$

$P=nh\nu n=\frac{P}{h\nu }=\frac{20\times {10}^3}{6.6\times {10}^{-34}\times 99\times {10}^6}=\frac{20\times {10}^3\times {10}^{34}}{660\times {10}^6}=\frac{1\times {10}^{31}}{33}=3\times {10}^{29}$