Question

# A triangle and parallelogram are constructed on the same base such that their area are equal. If the altitudes of the parallelogram is$100m$, then find the altitude of the triangle.

Open in App
Solution

## Step 1: Find the area of triangle and parallelogram Let the triangle and parallelogram have common base$b,$let the Altitude of the triangle is${h}_{1}$ and of parallelogram is${h}_{2}$ (which is equal to $100m$), thenArea of triangle$=\frac{1}{2}×b×{h}_{1}$Area of parallelogram$=bX{h}_{2}$Step 2: Find the altitude of the triangleAs per given $\frac{1}{2}XbX{h}_{1}=bX{h}_{2}\phantom{\rule{0ex}{0ex}}\frac{1}{2}XbX{h}_{1}=bX100\phantom{\rule{0ex}{0ex}}{h}_{1}=200$Hence, altitude of triangle$=200m$.

Suggest Corrections
7
Explore more